| Algebra 1 Notes
Chapter Eight
Section 8.1
Section 8.2
Section 8.3
Section 8.4
Section 8.5
Section 8.6
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Section 8.6 Digit
and Coin Problems
(Examples provided by Prentice
Hall)
Part I: Problem Solving: Digit and Coin Problems
Solve.
| Example
1 |
|
The
sum of the digits of a two-digit number is 10. If the digits are
reversed, the new number is 36 less than the original number.
Find the original number.
Let x = the tens digit. Let y = the ones digit.
x + y = 10
10x + y – 36 = 10y + x
Simplifying,
9x – 9y = 36
Multiplying the first equation by nine to make the y-terms
additive inverses,
| 9x
+ 9y = 90 |
| 9x
– 9y = 36 |
|
| 18x
= 126 |
| x
= 7 |
Substitute 7 for x in the first equation
and solve for y.
7 + y = 10
y = 3
The original number is 73. |
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| Example
2 |
A
collection of nickels and dimes is worth $3.95. There are 8 more
dimes than nickels. How many dimes and how many nickels are
there?
We use dollars as the unit of money. A nickel is worth 0.05
dollars. A dime is worth 0.10 dollars.
Let n be the number of nickels. Let d be the
number of dimes.
0.05n + 0.10d = 3.95
Multiply by 100 to clear the decimals.
| 5n
+ 10d = 395 |
|
(1) |
| d
= n + 8 |
(2) |
Substitute for d in (1).
5n + 10(n + 8) = 395
15n = 315
n = 21
Substitute in (2).
d = 29
There are 29 dimes and 21 nickels. |
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| Example
3 |
A
fork and knife weigh 50 grams and 70 grams, respectively. If the
set contains 20 knives and forks and weighs 1220 grams, how many
knives and forks are there?
Let f be the number of forks. Let k be the number
of knives.
| f
+ k = 20 |
|
(1) |
| 50f
+ 70k = 1220 |
(2) |
Multiply (1) by –50.
Add (1) and (2).
20k = 220
k = 11
Substitute in (1).
f + 11 = 20
f = 9
There are 9 forks and 11 knives. |
Take class notes.
Before starting your homework, rework the
examples that are illustrated in this section of your textbook and the
examples that I demonstrated in class.
Then do your homework.
Write down questions (examples or concept
that you do not understand).......then.............. Ask these questions
in class.
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