| Algebra 1 Notes
Chapter Eight
Section 8.1
Section 8.2
Section 8.3
Section 8.4
Section 8.5
Section 8.6
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Section 8.3
The Addition Method
(Examples provided by Prentice
Hall)
Part I: Using the Addition Method
Solve.
| Example
1 |
|
| 2x
+ 3y = 11 |
|
(1) |
| –2x
+ 9y = 1 |
(2) |
Add (1) and (2) to get
0 + 12y = 12
12y = 12
y = 1
Substitute in (1).
2x + 3(1) = 11
Solve for x.
2x = 8
x = 4
The solution (4, 1) checks.
|
Part II: Using the Multiplication Property First
Solve.
| Example
1 |
|
| 5x
+ 3y = 22 |
|
(1) |
| 5x
+ 6y = 34 |
(2) |
Multiply (2) by –1 to get –5x – 6y
= –34.
Add to equation (1).
0 – 3y = –12
y = 4
Substitute in (1).
5x + 3(4) = 22
5x = 10
x = 2
The solution (2, 4) checks. |
|
| Example
2 |
| –6x
+ 5y = 4 |
|
(1) |
| 3x
+ 4y = 11 |
(2) |
Multiply (2) by 2 to get 6x + 8y =
22. Now add this to (1).
0 + 13y = 26
y = 2
Substitute in (1).
–6x + 5(2) = 4
–6x = –6
x = 1
The solution (1, 2) checks. |
|
| Example
3 |
| 2x
+ 3y = 23 |
|
(1) |
| 3x
+ 5y = 37 |
(2) |
Multiply equation (1) by 3, and equation (2) by
–2 to get
| 6x
+ 9y = 69 |
|
(1) |
| –6x
– 10y = –74 |
(2) |
Add.
0 – y = –5
y = 5
Substitute in (1).
2x + 3(5) = 23
2x = 8
x = 4
The solution (4, 5) checks. |
Part III: Problem Solving
Solve.
| Example
1 |
|
Four
times a certain number is three more than twice another number.
The sum of the first number and twice the second number is 5.
Find the numbers.
Let x be the first number and let y be the second
number.
| 4x
= 2y + 3 |
|
(1) |
| x
+ 2y = 5 |
(2) |
When the first equation is written in standard
form the system becomes
| 4x
– 2y = 3 |
|
(1) |
| x
+ 2y = 5 |
(2) |
Add.
5x = 8
x = 8/5
Substitute in (2).
(8/5) + 2y = 5
Solve for y.
2y = 17/5
y =17/10
The solution is (8/5, 17/10). |
Take class notes.
Before starting your homework, rework the
examples that are illustrated in this section of your textbook and the
examples that I demonstrated in class.
Then do your homework.
Write down questions (examples or concept
that you do not understand).......then.............. Ask these questions
in class.
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